600(50+x)-600(50-x)=2500X^2

Solution for 600(50+x)-600(50-x)=2500X^2 equation:

600(50+x)-600(50-x)=2500x^2

We move all terms to the left:

600(50+x)-600(50-x)-(2500x^2)=0

determiningTheFunctionDomain
-2500x^2+600(50+x)-600(50-x)=0

We add all the numbers together, and all the variables

-2500x^2+600(x+50)-600(-1x+50)=0

We multiply parentheses

-2500x^2+600x+600x+30000-30000=0

We add all the numbers together, and all the variables

-2500x^2+1200x=0

a = -2500; b = 1200; c = 0;
Δ = b2-4ac
Δ = 12002-4·(-2500)·0
Δ = 1440000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1440000}=1200$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1200)-1200}{2*-2500}=\frac{-2400}{-5000}
=12/25
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1200)+1200}{2*-2500}=\frac{0}{-5000}
=0
$